题目内容

对诊断有助的检查,应选择

A. 白细胞计数及分类
B. 结核菌素试验
C. 关节腔穿刺抽液化验
D. 类风湿因子
E. X线检查

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已知在文件IN46.DAT中存有100个产品销售记录,每个产品销售记录由产品代码dm(字符型4位)、产品名称mc(字符型10位)、单价dj(整型)、数量sl(整型)、金过额je(长整型)几部分组成。其中,金额=单价×数量可计算得出。函数ReadDat()的功能是读取这100个销售记录并存入数组sell中。请编制函数SortDat(),其功能要求:按金额从大到小进行排列,若金额相同,则按产品代码从大到小进行排列,最终排列结果仍存入结构数组sell中,最后调用写函数WriteDat()把结果输出到文件 OUT46.DAT中。 注意:部分源程序已给出。 请勿改动主函数main()、读函数ReadDat()和写函数WriteDat()的内容。 试题程序: #include<stdio.h> #include<mem.h> #include<string.h> #include<conio.h> #include<stdlib.h> #define MAX 100 typedef struct char dm[5]; char mc[11]; int dj; int sl; long je; PRO; PRO sell[MAX]; void ReadDat(); void WriteDat(); void SortDat() void main () memset(sell,0,sizeof(sell)); ReadDat(); SortDat(); WriteDat(); void ReadDat() FILE *fp; char str[80],ch[11]; int i; fp=fopen("IN46.DAT","r"); for(i=0;i<100;i++) fgets(str, 80,fp); memcpy(sell[i].dm, str,4); memcpy(sell[i].mc,str+4,10); memcpy(ch, str+14, 4); ch[4]=0; sell[i],dj=atoi(ch); memcpy(ch,str+18,5); ch[5]=0; sell[i].sl=atoi(ch); sell[i].je=(long)sell[i].dj*sell[i].sl; fclose(fp); void WriteDat() FILE *fP; int i; fP=fopen("OUT46.DAT","w",); for(i=0;i<100;i++) fprintf(fp,"%s %s %4d %5d %101d\n",sell[i].dm, sell[i].mc,sell[i].dj,sell[i].sl,sell[i].je); fclose(fp);

A hundred years ago, chocolate was something

A. that only wealthy people could eat.
B. that people all eat like today.
C. nobody could affor

The chocolate were not produced

A. for more than ten years.
B. for less than ten years.
C. during the World War I

What is the problem

A. The nightshift manager is given too much work.
B. The operators are given too much work.
C. The machines are given too much work.

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