题目内容

Java通过过滤流对I/O访问提供______机制。

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案例分析题The Rational Unified Process (RUP) is a software engineering process, which captures many of best practices in modem software development. The notions of () and scenarios have been proven to be an excellent way to capture function requirements. RUP can be described in two dimensions - time and content. In the time dimension, the software lifecycle is broken into cycles. Each cycle is divided into four consecutive () which is concluded with a well-defined () and can be further broken down into () - a complete development loop resulting in a release of an executable product, a subset of the final product under development, which grows incrementally to become the final system. The content structure refers to the disciplines, which group () logically by nature. The notions of () and scenarios have been proven to be an excellent way to capture function requirements.

A. artifacts
B. use-cases
C. actors
D. workers

案例分析题Currently the Pentium chip or () , made by () , is the most common CPU though there are many other companies that produce processors for personal computers. One example is the CPU made by Motorola which is used in Apple computers. With faster processors the clock speed becomes more important. Compared to some of the first computers which operated at below 30 megahertz ( () ) the Pentium chips began at 75 megahertz in the late 1990g. As of mid 2003 speeds now exceed 3000 + megahertz or 3 gigahertz (check your local computer store for the latest speed) . It depends on the () that the chip is housed in, or the () , as to whether you are able to upgrade to a faster chip. The motherboard contains the circuitry and connections that allow the various component to communicate with each other. or the () , as to whether you are able to upgrade to a faster chip.

A. motherboard
B. centerboard
C. multiboard
D. cardboard

案例分析题在微机中,中断过程包括(),总线组成包括()。 在微机中,中断过程包括()

A. 中断请求、中断响应、中断处理、中断结束
B. 中断请求、中断处理、中断返回
C. 中断响应、中断处理、中断返回
D. 中断请求、中断响应、中断处理、中断返回

案例分析题若某CPU的有效地址长度为24位,则其寻址范围是(),其虚拟存储器的容量为()。 若某CPU的有效地址长度为24位,则其寻址范围是()

A. 0~222-1
B. 0~222
C. 0~224-1
D. 0~224

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