The contents of accumulator and CY are 65H and 0 respectively. After execution of instruction “SUBB A, #78H”, the contents of A will be( )
A. EDH
B. DEH
C. 19H
D. 78H
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The contents of accumulator, R0 and RAM location 30H are F0H, 30H, and AAH respectively. After execution of an instruction “XCH A, @R0”, the contents of A will be( )
AAH
B. F0H
C. 30H
D. 78H
The contents of accumulator, R1 and RAM location 40H are F0H, 40H, and 0FH respectively. After execution of an instruction “XCHD A, @R1”, the contents of A will be( )
A. 00H
B. F0H
C. 0FH
D. FFH
The contents of accumulator and CY are FEH and 1 respectively. After execution of instruction “RR A”, the contents of A will be ( )
A. FCH
B. 7FH
C. F1H
D. FDH
After execution of following two instructions “MOV A, #0FH” and “ANL A, #2CH”, the contents of the accumulator will be ( )
A. 11010111B
B. 11011010B
C. 00001100B
D. 00101000B