题目内容

有如下程序：#include using namespace std;class A {public:virtual void func1() { cout<<"A1"; }void func2() { cout<<"A2"; }};class B:public A {public:void func1() { cout<<"B1"; }void func2() { cout<<"B2"; }};int main() {A *p=new B;p->func1();p->func2();delete p;return 0;}执行这个程序的输出结果是()。

A. B1B2
B. A1A2
C. B1A2
D. A1B2

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有如下程序：#include using namespace std;class Base{public:void fun1() { cout<<"Base\n"; }virtual void fun2() { cout<<"Base\n"; }};class Derived : public Base {public:void fun1() { cout<<"Derived\n"; }void fun2() { cout<<"Derived\n"; }};void f(Base& b) { b.fun1(); b.fun2(); }int main(){Derived obj;f(obj);return 0;}执行这个程序的输出结果是()。

A. Base Base
Base Derived
C. Derived Base
Derived Derived

有如下程序：#include using namespace std;class Base {public:void output() { cout<<1; }virtual void Print() { cout<<′B′; }};class Derived : public Base {public:void output() { cout<<2; }void Print() { cout<<′D′; }};int main(){Base *ptr=new Derived;ptr->output();ptr->Print();delete ptr;return 0;}执行这个程序的输出结果是()。

A. 1B
B. 1D
C. 2B
D. 2D

在一个有向图中，所有顶点的入度和等于所有结点的出度之和的（）倍。

A. 1/2
B. 1
C. 2
D. 3

一个图的边集为{,,,,,}，从顶点a出发进行深度优先遍历搜索得到的顶点序列为【】，从顶点a出发进行广度优先搜索遍历得到的顶点序列为【】。（答案不唯一）acefbd