有以下程序#include <stdlib.h>struct NODE{int num;struct NODE *next;};main(){ struct NODE *p,*q,*r;int sum=0;p=(struct NODE *)malloc(sizeof(struct NODE));q=(struct NODE *)malloc(sizeof(struct NODE));r=(struct NODE *)malloc(sizeof(struct NODE));p->num=1;q->num=2;r->num=3;p->next=q;q->next=r;r->next=NULL;sum+=q->next->num;sum+=p->num;printf(“%d\n”,sum);}执行后的输出结果是
A. 3
B. 4
C. 5
D. 6
有以下程序 void f(int a[ ],int i,int j) { int t; if(i<j) { t=a[i]; a[i]=a[j];a[j]=t; f(a,i+1,j-1); } } main() { int i,aa[5]={1,2,3,4,5}; f(aa,0,4); for(i=0;i<5;i++) printf(“%d,”,aa[i]); printf(“\n”); } 执行后输出结果是()
A. 5,4,3,2,1,
B. 5,2,3,4,1,
C. 1,2,3,4,5,
D. 1,2,3,4,5,