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The "Real" Piryanka Sundarajan
By Ranjit Singh, Staff Reporter
While much has been written about famous media mogul Piryanka Sundarajan, little is known about many aspects of her private life.
Ms. Sundarajan is married and has two sons. (145) her childhood in Indonesia, where her father was posted with the National Bank of India.
Ms. Sundarajan retains fond memories of the country. "I was (146) by everything about Indonesia—especially the architecture."
At United Media Corporation, (147) Ms. Sundarajan founded as a young college graduate, she is recognized as a tough negotiator. However, she is even better known for her ability to (148) quality employees satisfied: hardly one person from the company's senior staff—be it director, general manager, or deputy general manager—has left the organization in the last fifteen years. Employees attribute this to Ms. Sundarajan's outstanding leadership qualities.
(45)
New Administrative Employee Training
Monday, August 7
Tour of Packaging Facility
9:00-9:30 A.M. Meet in cafeteria; continental breakfast will be provided.
9:30 A.M. Shuttle bus leaves for packaging facility.
10:00-10:20 A.M. Tom Miller, Vice President of Operations, discusses facility goals and recent improvements.
10:20-10:30 A.M. Meet with tour guides (all guides are experienced facility
employees).
10:30-11:15 A.M. Group A: Visit publishing area.
Group B: Visit distribution center.
Group C: Visit packaging area (protective gear required).
11:15 A.M.-12:00 noon Group A: Visit distribution center.
Group B: Visit packaging area (protective gear required).
Group C: Visit publishing area.
12:00 noon-1:00 P.M. Lunch with Anna Towers, Coordinator of Packaging Activities.
1:00-1:45 P.M. Group A: Visit packaging area (protective gear required).
Group B: Visit publishing area.
Group C: Visit distribution center.
1:45-2:30 P.M. Panel discussion with directors of packaging, publishing, and distribution.
2:30 P.M. Shuttle bus returns to administrative offices.
What are new administrative employees scheduled to do？
From: Lettore Books Online [order-info@lettorebooks.com]
To: Andrea Polokov [apolokov@amail.com]
Subject: Order Confirmation
Dear Andrea Polokov:
This is to inform. you that we are in receipt of your order placed on December 2.
Your order confirmation number is YB-145970. Should you have any questions regarding your order, you will be asked to refer to this number.
Two of the titles you requested are currently in stock; these materials should ship within 1-3 days. However, the video title is on backorder. We expect that it should be available and shipped to you within the next 3 weeks. When your order is shipped, you will receive an e-mail detailing the date and method of shipment as well as the estimated delivery date.
For your convenience, you can track the status of your order online by visiting your account link at http://www.lettorebooks.com/acctinfo/login. There you can track shipment status, review estimated delivery dates, cancel unshipped items, and contact customer service 24 hours a day.
You can also call our customer service number at 1-800-555-2346. Service representatives are available Monday through Friday from 8:00 a.m. until 5:00 p.m.
Thank you once again for shopping with us.
Sincerely,
Lettore Books Online
What does this e-mail confirm？
阅读以下说明和C程序，将应填入(n)处的字句写在答题纸的对应栏内。
【说明】
假设需要将N个任务分配给N个工人同时去完成，每个人都能承担这N个任务，
但费用不同。下面的程序用回溯法计算总费用最小的一种工作分配方案，在该方案中，为每个人分配1个不同的任务。
程序中，N个任务从0开始依次编号，N个工人也从0开始依次编号，主要的变量说明如下：
c[i][j]：将任务i分配给工人j的费用；
task[i]：值为0表示任务i未分配，值为j表示任务i分配给工人j；
worker[k]：值为0表示工人k未分配任务，值为1表示工人k已分配任务；
mincost：最小总费用。
【C程序】
#include＜stdio.h＞
#define N 8 /*N表示任务数和工人数*/
int c[N][N]；
unsigned int mincost=65535； /*设置min的初始值，大于可能的总费用*/
int task[N]，temp[N]，workerIN]；
void Plan(int k，unsigned Int cost)
{ int i；
if ((1)&&cost＜mincost){
mincost=cost；
for (i=0；i＜N；i++) temp[i]：task[i]；
}
else{
for(i=0；i＜N；i++) /*分配任务k*/
if (worker[i]＝0&&(2)){
worker[i]=1； task[k]=(3)；
Plan((4)，cost+c[k][i])；
(5)； task[k]=0；
}/*if*/
}
}/*Plan*/
void main()
{int i，j；
for (i=0；i＜N；i++) { /*设置每个任务由不同工人承担时的费用及全局数组的初值*/
worker[i]=0；task[i]=0； temp[i]=0；
for(j=0；j＜N；j++)
scanf ("%d"，&c[i][j])；
}
Plan (0，0)； /*从任务0开始分配*/
printf("\n最小费用=%d\n"，mincost)；
for(i二0；i＜N；i++)
pnntf("Task%d iB assigned toWorker%d\n",i,temp[i])；
}/*main*/
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