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To: Management Team From: Jenny Ross, CEO Dear Managers, I have some unfortunate news to pass on to all of you. As you all know, we need to cut expenditure, or else the company will continue to operate at a loss. (28) , I have decided to go ahead with the employee layoffs. We should aim to maintain a full-time staff of around 450. That means each of you will need to (29) 10 percent of the employees in your department. As you know your own employees so well’, I will allow you to make your own decisions on this matter. I hope that you will consider issues such as employee performance, loyalty, and attitude. I realize that this will not be an easy task for you. However, this drastic (30) is necessary to secure the future of our company. Regards, Jenny Ross
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字符串str由数字字符组成(长度不超过5个字符)，可看做任意进制的数，请补充函数proc()，该函数的功能是：把str字符串从二进制转换为十进制的数，结果保存在数组xx中，由函数返回转换后数组xx的实际长度。其中x表示str原来的进制，y表示要转换成的进制。例如，输入str="1011", x=2，y=10，结果输出：11。 注意：部分源程序已给出。 请勿改动主函数main和其他函数中的任何内容。 试题程序： #include＜stdio.h＞ #include＜stdlib.h＞ #include＜string.h＞ #define M 8 int xx[M]; int proc(char*str, int x, int y) int sum; int i=0; char *p=str; for(i=0; i＜M; i++) xx[i]=0; sum= (1) ; p++; while(*p) sum=sum*x+*p-’0’; p++; i=0; while(sum!=0) xx[i]= (2) ; (3) ; i++; return i; void main() char str[6]; int i; int n; int x; int y; printf("Enter a string made up of ’0’ to ’9’ digits character: "); gets(str); if(strlen(Str)＞5) printf("Error: string too longer!, please input again!\n\n"); exit(0); for(i=0; slr[i]; i++) if(str[i]＜’0’||str[i]＞’9’) printf("Error: %c not is ’0’to ’9’ digits character! \n\n", str[i]); exit(0); printf("The original string: "); puts(str); printf("\nINPUT x="); scanf("%d", &x); printf("\nINPUT y="); scanf("%d", &y); n=proc(str, X, y); printf("\n%s is convered to", str); for(i=n=1; i＞=0; i--) printf("%d\n", xx[i]/n);
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