已知在0.5mol/LH2SO4介质中,φθ(Ce4+/Ce3+)=1.44V,φθ(Fe3+/Fe2+)=0.68V。计算此条件下以0.100mol/LCe4+滴定0.100mol/LFe2+至化学计量点时,反应物及滴定产物的浓度()
A. [Ce]=[Fe]=1.8×10mol/L,[Ce]=[Fe]≈0.050mol/L
B. [Ce]=[Fe]≈0.050mol/L,[Ce]=[Fe]=2.0×10mol/L
C. [Ce]=[Fe]=0.047mol/L,[Ce]=[Fe]=0.003mol/L
D. [Ce]=[Fe]=0.047mol/L,[Ce]=[Fe]=0.003mol/L