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3 Assuming that the two-dimensional array A[1...100,1...100] is stored in row-major order, and each element occupies 2 storage units, and the base address is 10, then LOC[5,5]=( ).

A. 808
B. 818
C. 1010
D. 1020

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4 Each element of the two-dimensional array A is a string of 6 characters, the row subscript i ranges from 0 to 8, and the column subscript j ranges from 1 to 10, so storing A requires at least ( ) bytes.

A. 90
B. 180
C. 240
D. 540

5 Each element of the two-dimensional array A is a string of 6 characters, the row subscript i ranges from 0 to 8, and the column subscript j ranges from 1 to 10, then the 8th column of A and the 5th row occupy ( ) bytes.

A. 54
B. 108
C. 114
D. 150

6 Each element of the two-dimensional array A is a string of 6 characters, the row subscript i ranges from 0 to 8, and the column subscript j ranges from 1 to 10, Then the address of element A[8,5] with row-major order is the same as element ( ) with column-major order.

A[3,10]
B. A[8,5]
C. A[5,8]
D. A[0,9]

7 Let A be a n-order symmetric matrix, its elements of the lower triangle (including all elements on the main diagonal) are stored in row-major order in the one-dimensional array B[1...(n+1)/2]. If the value of aij((1≤i≤j≤n)) is stored in B[k], then the calculation formula of k is ().

A. j(j-1)/2+i
B. i(i-1)/2+j
C. i(i+1)/2+j
D. j(j+1)/2+i

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