题目内容

Although a given waveform may contain frequencies over a very broad range, as a practical matter any transmission system will be able to accommodate only a limited band of () . This, in turn, limits the data rate that can be carried on the transmission () . A square wave has an infinite number of frequency components and hence an infinite () .However, the peak amplitude of the kth frequency component, kf, is only 1/k, so most of the () in this waveform is in the first few frequency components. In general, any digital waveform will have () bandwidth. If we attempt to transmit this waveform as a signal over any medium, the transmission system will limit the bandwidth that can be transmitted. Although a given waveform may contain frequencies over a very broad range, as a practical matter any transmission system will be able to accommodate only a limited band of () .

A. frequencies
B. connections
C. diagrams
D. resources

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9()

A. rather
B. quite
C. much
D. really

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在IPv6的单播地址中有两种特殊地址,其中地址0:0:0:0:0:0:0:0表示(),地址0:0:0:0:0:0:0:1表示()。 地址0:0:0:0:0:0:0:1表示()

A. 不确定地址,不能分配给任何结点
B. 回环地址,结点用这种地址向自身发送IPv6分组
C. 不确定地址,可以分配给任何地址
D. 回环地址,用于测试远程结点的连通性

萧某是甲纸业有限公司工人,于2008年10月20日0时至8时上夜班。凌晨5时45分左右,正坐在车间内打瞌睡的萧某被纸辊砸中,当场昏迷。经医院诊断,萧某伤情为腹部闭合性损伤,需停工在家静养3个月。萧某在医院住院治疗期间,甲公司支付了此期间发生的医疗费用和护理费用。但甲公司主张,萧某在上班时间打瞌睡,严重违反了公司劳动纪律,拒绝给予萧某工伤待遇,双方发生纠纷。另查明:甲公司自开业以来没有为其职工办理工伤保险;甲公司2008年度职工月平均工资为800元,萧某月工资为900元,当地2008年度职工月平均工资为1500元,当地2008年度城镇居民月平均消费支出为500元。 如果认定萧某可以享受停工留薪待遇,依照《工伤保险条例》规定的计算方法,其工资总额应为()元。

A. 1500
B. 2400
C. 2700
D. 4500

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