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Think twice next time someone asks you for "five minutes of your time" it could cost you more than you think. A British professor has (36) a mathematical (37) to help people find out exactly how much an hour of their time is worth. Professor Ian Walker of Warwick University (38) the value of time after research showed that over 80 percent of (39) would buy more time if they could (40) it. "Traditionally, wages or salaries have given an (41) of how we are valued at work," Walker, an (42) professor, said in a statement. "How ever, by looking at salaries against taxation, the cost of living and (43) variations, (44) "The formula could help in making decisions, such as whether to cook a meal or to get a takeaway, or whether to take public transport or a taxi. Visitors to www. barclay card. co. uk/timeismoney can (45) . For example, for a professional working in London and earning 25,000 pounds a year, an hour would be worth 6.44 pounds, according to the Web site. Cooking dinner would cost 5.37 pounds - cheaper to get a takeaway, (46) Brushing your teeth comes at 32 pence perhaps hard to find someone to do it for you for less.

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工娱治疗不适用于哪些患者？

Questions 11 to 18 are based on the conversation you have just heard.

A. He hasn’ t decided on a topic for his composition.
B. He has fallen behind others in English class.
C. He hasn’t made up his mind as to what to write about.
D. The book he borrowed will be due tomorrow.

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已知在文件IN94.DAT中存有若干个(个数＜200)4位数字的正整数，函数ReadDat()的功能是读取这若干个正整数并存入数组xx中。请编制函数CalValue()，其功能要求：(1)求出该文件中共有多少个正整数totNum；(2)求m这些数中的各位数字之和是偶数的数的个数totCnt，以及满足此条件的这些数的算术平均值totPjz，最后调用函数WriteDat()把所求的结果输出到文件OUT94.DAT中。注意：部分源程序已给出。请勿改动主函数main()、读函数ReadDat()和写函数WriteDat()的内容。试题程序： #include ＜stdio.h＞ #include ＜stdlib.h＞ #define MAXNUM 200 int xx[MAXNUM]； int totNum=0；/文件IN94.DAT中共有多少个正整数/ int totCnt=0；/符合条件的正整数的个数/ double totPjz=0.0；/平均值/ int ReadDat(void)； void Writedat(void)； void CalValue() void main() int i； system("CLS")； for(i=0；i＜MAXNUM；i + +) xx[i]=0； if(Readdat()) printf("数据文件IN94.DAT不能打开!\007\n")； return； CalValue()； printf("文件IN94.DAT中共有正整数=% d个\n"，totNum)； printf("符合条件的正整数的个数=% d个\n"，totCnt)； printf("平均值=% .21f\n"，totPjz)； Writedat()； int Readdat(void) FILE * fp； int i=0； if((fp=fopen("IN94.DAT"，"r"))==NULL) return 1； while(! feof(fp)) fscanf(fp，"% d，"，&xx[i + +])； fclose(fp)； return 0； void Writedat(void) FILE * fp； fp=fopen("OUT94.DAT"，"w")； fprintf(fp，"% d\n% d\n% .21f\n"，totNum，totCnt，totPjz)； fclose(fp)；

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Questions 11 to 18 are based on the conversation you have just heard.

A. She will take subway.
B. She will hurry to the conference.
C. She will skip the conference and go sightseeing.
D. She will take a bus.

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