题目内容
A company purchases a truck with a useful life of 5 years. The cost was $100000 with an estimated salvage value of $10000. Using the double declining balance method and the sum of the years’ digits method, what is the depreciation in year 2 Double-Declining Sum of Years’ Digits ①A. $ 40000 $ 24000 ②B. $ 24000 $ 45000 ③C. $ 24000 $ 24000
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已知在文件IN1.DAT中存有100个产品销售记录，每个产品销售记录由产品代码dm(字符型4位)、产品名称mc(字符型10位)、单价dj(整型)、数量s1(整型)、金额je(长整型)五部分组成。其中：金额＝单价×数量。函数ReadDat()的功能是读取这100个销售记录并存入结构数组.sell中。请编制函数SortDat()，其功能要求：按产品名称从小到大进行排列，若产品名称相同，则按金额从小到大进行排列，最终排列结果仍存入结构数组sell中，最后调用函数WriteDat()把结果输出到文件OUT1.DAT中。 注意：部分源程序已给出。请勿改动主函数main()、读数据函数ReadDat()和输出数据函数WriteDat()的内容。 [试题程序] include #include #include #include #include #define MAX 100 typedef struct char dm[5]; /*产品代码* / char mc[11]; /*产品名称*/ int dj; /*单价* / int si; /*数量*/ long je; /*金额*/ PRO; PRO sell[-MAX]; void ReadDat() ; void WriteDat() ; void SortDat() main() memset(sell,0,sizeof(sell)); ReadDat(); SortDat(); WriteDat(); void ReadDat() FILE *fp; char str[80],ch[11]; int i; fp=fopen("IN1.DAT","r"); for (i=0;i＜100;i++) fgets(str,80,fp) memcpy(sell[i].dm,str,4) memcpy(sell[i].mc,str + 4,10); memcpy(ch,str + 14,4);ch[4]=0; sell[i].dj=atoi(ch) memcpy(ch,str +18,5);ch[5]=0; sell[i].s1=atoi(ch); sell[i].je=(long)sell[i].dj * sell[i].s1; fclose(fp); void WriteDat() FILE * fp; int i; fp=fopen("OUT1.DAT","w"); for(i=0;i<100;i++) fprintf(fp,"%s%s%4d%5d%101d\n",sell[i].dm,sell[i].mc,sell[i].dj,sell[i].s1,sell[i].je) fclose(fp);
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