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以下是某C++程序，用来判定用户口令，请仔细阅读程序并完成要求。 //// // 口令检验程序 // // 文件名：password_check. cpp // //// #include＜iostream. h＞ #include＜string. h＞ //// // 主函数 // //// void main(void) { char password[128]={’\0/}； cout＜＜“请输入您的口令："； cout. flush()； while(true){ cin. getline(password，128，’\n’)； if(strlen(password)＜6) //口令长度少于6位 { cout＜＜"您的用户口令少于6个字符!"＜＜endl； cout＜＜"请重新输入："； cout. flush()； }else{ bool capital=false； //检验是否有大写字母 bool lowercase=false； //检验是否有小写字母 bool digit=false； //检验是否有数字 for(unsigned int i=0；i＜strlen(password)；i++){ if(password[i]＞=’A’＆＆password[i]＜=’Z’) capital=true； if(passwordEi]＞="a"＆＆password[i]＜=’Z’) lowercase=true； if(password[i]＞=’0’＆＆password[i]＜=’9’) digit=true； } //判断用户输入的口令中缺少哪中字符 if(capital){ cout＜＜"您的用户口令中没有大写字母!"＜＜endl； cout＜＜"请重新输入："； }else if(lowercase){ cout＜＜"您的用户口令中没有小写字母!"＜＜endl； cout＜＜"请重新输入："； }else if(digit){ cout＜＜"您的用户口令中没有数字!"＜＜endl； cout＜＜"请重新输入："； }else{ cout＜＜"您的口令满足要求!"＜＜endl； break； } } } } 设计一组测试用例，使该程序所有函数的语句覆盖率和分支覆盖率均能达到100%。如果认为该程序的语句或分支覆盖率无法达到100%，需说明理由。

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