政府的最高限价的后果有( )
A. 政府最高限价高于均衡价格
B. 产品将供不应求
C. 政府最高限价低于均衡价格
D. 政府需要对负责提供产品的企业进行补贴
E. 政府需要对消费者实行准入限制
在供给不变的前提下,若需求增加,则新的均衡价格上升,均衡数量增加()
#include #include #include #include #include using namespace std; int a[100005]; int b[100005]; int val[100005][20]; int get_bit[1 <= 0; i--) { int j; val[i][0] = b[i]; for (j = 1; j = r) { newl = r; } int ans1 = b[newl - 1] - b[l] + 1; int k; if (r > newl) { k = get_bit[r - newl]; } else { printf("%d\n", ans1); continue; } printf("%d\n", max(ans1, max(val[newl][k], val[r - (1 <
A. #include #include #include #include #include using namespace std; int a[100005]; int b[100005]; int val[100005][20]; int get_bit[1 <= 0; i--) { int j; val[i][0] = b[i]; for (j = 1; j = r) { newl = r; } int ans1 = b[newl - 1] - b[l] + 1; int k; if (r > newl) { k = get_bit[r - newl]; } else { printf("%d\n", ans1); continue; } printf("%d\n", max(ans1, max(val[newl][k], val[r - (1 < #include #include #include #include using namespace std; int a[100005]; int b[100005]; int val[100005][20]; int get_bit[1 <= 0; i--) { int j; val[i][0] = b[i]; for (j = 1; j = r) { newl = r; } int ans1 = b[newl - 1] - b[l] + 1; int k; if (r > newl) { k = get_bit[r - newl]; } else { printf("%d\n", ans1); continue; } printf("%d\n", max(ans1, max(val[newl][k], val[r - (1 < #include #include #include #include using namespace std; int a[100005]; int b[100005]; int val[100005][20]; int get_bit[1 <= 0; i--) { int j; val[i][0] = b[i]; for (j = 1; j = r) { newl = r; } int ans1 = b[newl - 1] - b[l] + 1; int k; if (r > newl) { k = get_bit[r - newl]; } else { printf("%d\n", ans1); continue; } printf("%d\n", max(ans1, max(val[newl][k], val[r - (1 < #include #include #include #include using namespace std; int a[100005]; int b[100005]; int val[100005][20]; int get_bit[1 <= 0; i--) { int j; val[i][0] = b[i]; for (j = 1; j = r) { newl = r; } int ans1 = b[newl - 1] - b[l] + 1; int k; if (r > newl) { k = get_bit[r - newl]; } else { printf("%d\n", ans1); continue; } printf("%d\n", max(ans1, max(val[newl][k], val[r - (1 <
titi
A. titi
B. titi
C. #include #include #include #include #include using namespace std;int a[100005];int b[100005];int val[100005][20];int get_bit[1 << 17];int main(){ freopen("world_cup_2.in", "r", stdin); freopen("world_cup_2.out", "w", stdout); int n; scanf("%d", &n); int i; for (i = 0; i < 17; i++) { int j; for (j = (1 << i); j < (1 << (i + 1)); j++) { get_bit[j] = i; } } for (i = 0; i < n; i++) { scanf("%d", &a[i]); } sort(a, a + n); for (i = 0; i < n; i++) { if (i == 0) { b[i] = 1; } else if (a[i] != a[i - 1]) { b[i] = 1; } else { b[i] = b[i - 1] + 1; } } for (i = n - 1; i >= 0; i--) { int j; val[i][0] = b[i]; for (j = 1; j < 20; j++) { if ((i + (1 << (j - 1))) <= n) { val[i][j] = max(val[i][j - 1], val[i + (1 << (j - 1))][j - 1]); } else { val[i][j] = val[i][j - 1]; } } } int m; scanf("%d", &m); for (i = 0; i < m; i++) { int l, r; scanf("%d%d", &l, &r); l--; l = n - l; r = n - r; swap(l, r); int newl = upper_bound(a, a + n, a[l]) - a; if (newl >= r) { newl = r; } int ans1 = b[newl - 1] - b[l] + 1; int k; if (r > newl) { k = get_bit[r - newl]; } else { printf("%d\n", ans1); continue; } printf("%d\n", max(ans1, max(val[newl][k], val[r - (1 << k)][k]))); } return 0;}
D. ```#include #include #include #include #include using namespace std;int a[100005];int b[100005];int val[100005][20];int get_bit[1 << 17];int main(){ freopen("world_cup_2.in", "r", stdin); freopen("world_cup_2.out", "w", stdout); int n; scanf("%d", &n); int i; for (i = 0; i < 17; i++) { int j; for (j = (1 << i); j < (1 << (i + 1)); j++) { get_bit[j] = i; } } for (i = 0; i < n; i++) { scanf("%d", &a[i]); } sort(a, a + n); for (i = 0; i < n; i++) { if (i == 0) { b[i] = 1; } else if (a[i] != a[i - 1]) { b[i] = 1; } else { b[i] = b[i - 1] + 1; } } for (i = n - 1; i >= 0; i--) { int j; val[i][0] = b[i]; for (j = 1; j < 20; j++) { if ((i + (1 << (j - 1))) <= n) { val[i][j] = max(val[i][j - 1], val[i + (1 << (j - 1))][j - 1]); } else { val[i][j] = val[i][j - 1]; } } } int m; scanf("%d", &m); for (i = 0; i < m; i++) { int l, r; scanf("%d%d", &l, &r); l--; l = n - l; r = n - r; swap(l, r); int newl = upper_bound(a, a + n, a[l]) - a; if (newl >= r) { newl = r; } int ans1 = b[newl - 1] - b[l] + 1; int k; if (r > newl) { k = get_bit[r - newl]; } else { printf("%d\n", ans1); continue; } printf("%d\n", max(ans1, max(val[newl][k], val[r - (1 << k)][k]))); } return 0;}```
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